soal trigonometri
 
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soal trigonometri

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Bls: soal trigonometri

Misal x = 18
cos 5x = cos 5.18
cos 5x = cos 90
cos 5x = 0
cos (x+4x) = 0
cosx.cos4x - sinx.sin4x = 0
cosx(2coskw 2x-1)-2sinxsin2xcos2x=0
cosx(2(2coskw x-1)-1)-4sinkw x.cosx(2coskw x-1) = 0
4cos^3 x - 3cosx -8sinkw x.cos^3 x +4sin kw x.cosx =0
4cos^3 x(1-2sinkw x) + cosx (4sinkw x-3) =0
4cos^3 x(2 coskw x -1) + cosx(4sinkw x - 3) = 0
8cos^5 x - 4cos^3 x +4cosx.sinkw x - 3cosx = 0 (cos x keluar)
cosx (8cos^4 x - 4cos^2 x + 4sin^2 x - 3) = 0

(i)cosx =0 ( TM )
(ii) 8cos^4 x - 4cos^2 x + 4sin^2 x - 3 = 0
8cos^4 x - 4cos^2 x +2(2sin^2 x -1) -1 = 0
8cos^4 x - 4cos^2 x +2(-cos2x) - 1 =0
8cos^4 x - 4cos^2 x +2(-2cos^2 x +1) - 1 = 0
8cos^4 x - 4cos^2 x -4cos^2 x +1 = 0
8cos^4 x - 8cos^2 x + 1 = 0
Gunakan rumus abc untuk mencari akar2 persamaan>
cos^2 x =( 8 + 4 akar 2)/16
= (2+akar 2)/4
cos x = 1/2
klo dihitung pake kalkulator sekitar 0.9>:l
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Bls: soal trigonometri

Biasanya di cover belakang buku paket kimia tuh ada rumus kimia macem gitu.
luckywinner
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Bls: soal trigonometri

Kutip:
Oleh rafed View Post
hal kek gini gak mungkin di afal pasti pk kalkulator
nga juga, hal kyk gini di mengerti dan pake hafalan juga bisa. knapa pake kalkulator kalo bisa cari jawaban nya tanpa kalkulator
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Reply With Quote     #14   Report Post  

Bls: soal trigonometri

yang ngasi soal siapa tuh..? bunuh aja
wkwkwkwkwk..
knightwhite2
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Bls: soal trigonometri

Rumit apa emang logika kita belum sampai ya?
lala_lulu
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